How do you write y=3/8x-3/4 in standard form?

1 Answer
Jun 28, 2015

y=3/8x-3/4 in standard form is 3x-8y=6.

Explanation:

Standard form for a linear equation is Ax+By=C.

y=3/8x-3/4

Simplify 3/8x to (3x)/8.

Subtract (3x)/8 from both sides of the equation.

(-3x)/8+y=-3/4

Multiply both sides by -1.

(-3x)/8(-1)+y(-1)=-3/4(-1) =

(3x)/8-y=3/4

Multiply both sides by 8.

((3x)*8)/8-y(8)=((3)*8)/4 =

((3x)*cancel8^1)/(cancel 8^1)-y(8)=((3)*cancel8^2)/(cancel4^1) =

3x-8y=6