How do you write $y=3/8x-3/4$ in standard form?

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Answer 1 · 2015-06-28T06:50:55

$y=3/8x-3/4$ in standard form is $3x-8y=6$ .

Standard form for a linear equation is $Ax+By=C$ .

$y=3/8x-3/4$

Simplify $3/8x$ to $(3x)/8$ .

Subtract $(3x)/8$ from both sides of the equation.

$(-3x)/8+y=-3/4$

Multiply both sides by $-1$ .

$(-3x)/8(-1)+y(-1)=-3/4(-1)$ =

$(3x)/8-y=3/4$

Multiply both sides by $8$ .

$((3x)*8)/8-y(8)=((3)*8)/4$ =

$((3x)*cancel8^1)/(cancel 8^1)-y(8)=((3)*cancel8^2)/(cancel4^1)$ =

$3x-8y=6$

How do you write y=3/8x-3/4y=3/8x-3/4 in standard form?