How do you write $(x^2-9) / ( |x+3| )$ as a piecewise function?

Question

2013 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-18T10:11:49

$f(x)=x-3$ if $x > -3$ and $f(x)=-(x-3)$ if $x<-3$

Not that

$(x+3)/|x+3|=1$ if $x > -3$

$(x+3)/|x+3|=-1$ if $x<-3$

How do you write (x^2-9) / ( |x+3| )(x^2-9) / ( |x+3| ) as a piecewise function?