How do you write $x^{2} - 8 x - x y + 8 y$ $x^2-8x-xy+8y$ in factored form?

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How do you write $x^{2} - 8 x - x y + 8 y$ $x^2-8x-xy+8y$ in factored form?

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Answer 1 · 2015-09-18T17:04:26

It is $x^{2} - 8 x - x y + 8 y = (x^{2} - x y) - 8 (x - y) = x (x - y) - 8 (x - y) = (x - 8) (x - y)$ $x^2-8x-xy+8y=(x^2-xy)-8(x-y)=x(x-y)-8(x-y)=(x-8)(x-y)$

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How do you write $x^{2} - 8 x - x y + 8 y$ $x^2-8x-xy+8y$ in factored form?

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How do you write $x^{2} - 8 x - x y + 8 y$ $x^2-8x-xy+8y$ in factored form?