How do you write the trigonometric form in complex form #8(cos((pi)/6)+isin((pi)/6)))#?

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Answer 1 · 2016-11-28T17:32:07

The answer is #=sqrt3/4+i/4#

We calculate

#cos(pi/6)=sqrt3/2#

#sin(pi/6)=1/2#

Therefore,

#z=8(cos(pi/6)+i(sin(pi/6))#

#=8(sqrt3/2+i*1/2)#

#=sqrt3/4+i/4#