How do you write the trigonometric form in complex form #6(cos((5pi)/6)+isin((5pi)/6)))#?

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How do you write the trigonometric form in complex form #6(cos((5pi)/6)+isin((5pi)/6)))#?

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Answer 1 · 2016-10-29T12:26:03

THe complex form is #-3sqrt3+3i#

Explanation:

The trigonometric form is #z=r(costheta+isintheta)#
The complex form is #z=a+ib#
so we have to put the values of #costheta# and #sintheta#
#cos((5pi)/6)=-cos( pi/6)=-sqrt3/2#
and #sin((5pi)/6)=sin(pi/6)=1/2#

So we have #z=6((-sqrt3/2)+i/2)=-3sqrt3+3i#

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How do you write the trigonometric form in complex form #6(cos((5pi)/6)+isin((5pi)/6)))#?

1 Answer

Explanation:

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