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How do you write the trigonometric form in complex form #4(cos((3pi)/2)+isin((3pi)/2)))#?

1 Answer

Jan 6, 2017

The answer is #=-4i#

Explanation:

Let #z=4(cos((3pi)/2)+isin((3pi)/2))#

#cos((3pi)/2)=0#

#sin((3pi)/2)=-1#

Therefore,

#z=4(0-1*i)#

#z=-4i#

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