How do you write the standard form of a line given x-intercept= -5 , y-intercept= -7?

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How do you write the standard form of a line given x-intercept= -5 , y-intercept= -7?

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Answer 1 · 2016-07-07T10:23:47

The equation of the line is #y= -7/5*x - 7#

Explanation:

The co ordinate of x-intercept is#( -5,0)#
The co ordinate of y-intercept is #(0,-7)#
The slope of the line is #m= (y_2-y_1)/(x_2-x_1) = (-7-0)/(0 +5) = -7/5#
Let the equation of the line is #y=mx+c ; m= -7/5 ; c= -7 :.# The equation of the line is #y= -7/5*x - 7# graph{-7/5*x-7 [-20, 20, -10, 10]} [Ans]

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How do you write the standard form of a line given x-intercept= -5 , y-intercept= -7?

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