How do you write the standard form of a line given x intercept = -5, y intercept = -5?

1 Answer
Jim G.
Mar 30, 2018

#x+y=-5#

Explanation:

#"the equation of a line in "color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#

#"where A is a positive integer and B, C are integers"#

#"obtain the equation in "color(blue)"slope-intercept form"#

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#"to calculate the slope use the "color(blue)"gradient formula"#

#•color(white)(x)m=(y_2-y_1)/(x_2-x_1)#

#"let "(x_1,y_1)=(-5,0)" and "(x_2,y_2)=(0,-5)#

#rArrm=(-5-0)/(0-(-5))=(-5)/5=-1#

#"using "m=-1" and "b=-5#

#rArry=-x-5larrcolor(red)"in slope-intercept form"#

#"add x to both sides"#

#x+y=cancel(-x)cancel(+x)-5#

#rArrx+y=-5larrcolor(red)"in standard form"#

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