How do you write the standard form of a line given x-intercept=3 , y-intercept=2?
1 Answer
Dec 14, 2017
Explanation:
#"the equation of a line in "color(blue)"standard form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#
#"where A is a positive integer and B, C are integers"#
#"the equation of a line in "color(blue)"slope-intercept form"# is.
#•color(white)(x)y=mx+b#
#"where m is the slope and b the y-intercept"#
#"to calculate m use the "color(blue)"gradient formula"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(m=(y_2-y_1)/(x_2-x_1))color(white)(2/2)|)))#
#"let "(x_1,y_1)=(3,0)" and "(x_2,y_2)=(0,2)#
#rArrm=(2-0)/(0-3)=-2/3#
#rArry=-2/3x+2larrcolor(red)"in slope-intercept form"#
#"multiply through by 3"#
#rArr3y=-2x+6#
#rArr2x+3y=6larrcolor(red)"in standard form"#
