How do you write the standard form of a line given x intercept = 3, y intercept = 2?

1 Answer
May 27, 2017

#2x+3y-6=0#

Explanation:

#"the equation of a line in "color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By+C=0)color(white)(2/2)|)))#
where A is a positive integer and B, C are integers.

#"express the equation in "color(blue)"slope-intercept form"#

#• y=mx+b " where m represents the slope and b, the"#
#color(white)(xxxxxxxxxxx)"y-intercept"#

#"here " b=2" and m=-2/3#

#rArry=-2/3x+2larrcolor(red)" in slope-intercept form"#

#"add " 2/3x" to both sides"#

#2/3x+y=cancel(-2/3x)cancel(+2/3x)+2#

#rArr2/3x+y=2#

#"subtract 2 from both sides"#

#2/3x+y-2=0#

#"multiply ALL terms by 3"#

#rArr2x+3y-6=0larrcolor(red)" in standard form"#