How do you write the standard form of a line given (3, 6) and (0, –3)?

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How do you write the standard form of a line given (3, 6) and (0, –3)?

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Answer 1 · 2017-01-30T09:14:02

$y = 3 x - 3$ $y=3x-3$

Explanation:

$x_{1} = 3$ $x_1=3$
$y_{1} = 6$ $y_1=6$
$x_{2} = 0$ $x_2=0$
$y_{2} = - 3$ $y_2=-3$

$(y - y_{1}) = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1})$ $(y-y_1)=(y_2-y_1)/(x_2-x_1)(x-x_1)$

$(y - 6) = \frac{- 3 - 6}{0 - 3} (x - 3)$ $(y-6)=(-3-6)/(0-3)(x-3)$

$y - 6 = \frac{- 9}{- 3} (x - 3)$ $y-6=(-9)/(-3)(x-3)$

$y - 6 = 3 (x - 3)$ $y-6=3(x-3)$

$y - 6 = 3 x - 9$ $y-6=3x-9$

$y = 3 x - 9 + 6$ $y=3x-9+6$

$y = 3 x - 3$ $y=3x-3$

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How do you write the standard form of a line given (3, 6) and (0, –3)?

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