How do you write the standard form of a line given (3, 6) and (0, –3)?
1 Answer
Jan 30, 2017
#y=3x-3#
Explanation:
#x_1=3#
#y_1=6#
#x_2=0#
#y_2=-3#
#(y-y_1)=(y_2-y_1)/(x_2-x_1)(x-x_1)#
#(y-6)=(-3-6)/(0-3)(x-3)#
#y-6=(-9)/(-3)(x-3)#
#y-6=3(x-3)#
#y-6=3x-9#
#y=3x-9+6#
#y=3x-3#