How do you write the rectangular coordinates for the point: $(6, \frac{3}{2} π)$ $(6, 3/2 pi)$ ?

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How do you write the rectangular coordinates for the point: $(6, \frac{3}{2} π)$ $(6, 3/2 pi)$ ?

1 Answer

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Answer 1 · 2018-03-20T08:37:04

$(- 3, 3 \sqrt{3})$ $(-3,3sqrt(3))$

Explanation:

For given coordinates $(r, θ)$ $(r,theta)$ , $(r, θ) \to (x, y) \Rightarrow (r cos θ, r sin θ)$ $(r,theta)to(x,y)=>(rcostheta,rsintheta)$

$r = 6$ $r=6$
$θ = \frac{2 π}{3}$ $theta=(2pi)/3$

$(6, \frac{2 π}{3}) \to (x, y) \Rightarrow (6 cos (\frac{2 π}{3}), 6 sin (\frac{2 π}{3})) \equiv (- 3, 3 \sqrt{3})$ $(6,(2pi)/3)to(x,y)=>(6cos((2pi)/3),6sin((2pi)/3))-=(-3,3sqrt(3))$

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How do you write the rectangular coordinates for the point: $(6, \frac{3}{2} π)$ $(6, 3/2 pi)$ ?

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