How do you write the quadratic function in standard form #y=2/3(x-9)^2-4#? Algebra Polynomials and Factoring Polynomials in Standard Form 1 Answer marfre Jul 9, 2018 #y = 2/3x^2 - 12x + 50 # Explanation: Given: #y = 2/3(x - 9)^2 - 4# Distribute using #(a + b)^2 = a^2 + 2ab + b^2# #y = 2/3(x^2 -18x + 81) - 4# #y = 2/3x^2 - 2/3 * 18/1 x + 2/3 * 81/1 - 4# #y = 2/3x^2 -12 x + 54 - 4# #y = 2/3x^2 - 12x + 50 # Answer link Related questions What is a Polynomial? How do you rewrite a polynomial in standard form? How do you determine the degree of a polynomial? What is a coefficient of a term? Is #x^2+3x^{\frac{1}{2}}# a polynomial? How do you express #-16+5f^8-7f^3# in standard form? What is the degree of #16x^2y^3-3xy^5-2x^3y^2+2xy-7x^2y^3+2x^3y^2#? What is the degree of the polynomial #x^4-3x^3y^2+8x-12#? What is the difference between a monomial, binomial and polynomial? How do you write #y = 2/3x + 5# in standard form? See all questions in Polynomials in Standard Form Impact of this question 1978 views around the world You can reuse this answer Creative Commons License