How do you write the quadratic function in standard form $y=2/3(x-9)^2-4$ ?

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Answer 1 · 2018-07-09T04:41:27

$y = 2/3x^2 - 12x + 50$

Given: $y = 2/3(x - 9)^2 - 4$

Distribute using $(a + b)^2 = a^2 + 2ab + b^2$

$y = 2/3(x^2 -18x + 81) - 4$

$y = 2/3x^2 - 2/3 * 18/1 x + 2/3 * 81/1 - 4$

$y = 2/3x^2 -12 x + 54 - 4$

$y = 2/3x^2 - 12x + 50$

How do you write the quadratic function in standard form y=2/3(x-9)^2-4y=2/3(x-9)^2-4?