How do you write the point slope form of the equation of the line that passes through (4,2) and parallel to $y = - \frac{3}{4} x - 5$ $y=-3/4x - 5$ ?

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How do you write the point slope form of the equation of the line that passes through (4,2) and parallel to $y = - \frac{3}{4} x - 5$ $y=-3/4x - 5$ ?

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Answer 1 · 2015-03-31T17:42:30

Your line must have the same slope (=same inclination) of the given line and must intercept point ( $4, 2$ $4,2$ ):
So:
$y - y_{0} = m (x - x_{0})$ $y-y_0=m(x-x_0)$
$y - 2 = - \frac{3}{4} (x - 4)$ $y-2=-3/4(x-4)$ or:

$y = - \frac{3}{4} x + 5$ $y=-3/4x+5$

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How do you write the point slope form of the equation of the line that passes through (4,2) and parallel to $y = - \frac{3}{4} x - 5$ $y=-3/4x - 5$ ?

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How do you write the point slope form of the equation of the line that passes through (4,2) and parallel to y=-3/4x - 5y=−34x−5y=-3/4x - 5?

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How do you write the point slope form of the equation of the line that passes through (4,2) and parallel to $y = - \frac{3}{4} x - 5$ $y=-3/4x - 5$ ?