How do you write the point slope form of the equation given (-4,1) parallel to #y=-1/2x-1#?

1 Answer
Jim G.
Apr 29, 2017

#y-1=-1/2(x+4)#

Explanation:

The equation of a line in #color(blue)"point-slope form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#
where m represents the slope and # (x_1,y_1)" a point on the line"#

#"require to know the following fact."#

#color(red)(bar(ul(|color(white)(2/2)color(black)(" parallel lines have equal slopes")color(white)(2/2)|)))#

#y=-1/2x-1" is in slope-intercept form, that is"#

#y=mx+brArr" slope " = m=-1/2#

#"using " m=-1/2" and " (x_1,y_1)=(-4,1)#

#y-1=-1/2(x-(-4))#

#rArry-1=-1/2(x+4)larrcolor(red)" in point-slope form"#

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