How do you write the partial fraction decomposition of the rational expression x3x2+1x4x3?

1 Answer
Dec 23, 2015

x3x2+1x4x3=1x31x2+1x1

Explanation:

x3x2+1x4x3=x3x2x4x3+1x4x3

=x1x2x+1x3(x1)

=x1x(x1)+1x3(x1)

=1x+1x3(x1)

now focus on 1x3(x1)

1x3(x1)=Ax3+Bx2+Cx+Dx1

Multiply both side by x3(x1)

1=A(x1)+Bx(x1)+Cx2(x1)+Dx3

1=AxA+Bx2Bx+Cx3Cx2+Dx3

1=x3(C+D)+x2(BC)+x(AB)A

C+D=0
BC=0
AB=0
A=1

Just by looking we have

A=1
B=1
C=1
D=1

So

x3x2+1x4x3=1x31x2+1x1