How do you write the pair of parametric equations as a single equation in x and y given x=7t-7 and #y=7t^2-3#? Calculus Parametric Functions Derivative of Parametric Functions 1 Answer Eddie Sep 7, 2016 #y = x^2/7+2 x+4# Explanation: #x = 7t - 7 implies t = (x+7)/7# #y = 7t^2 - 3 = 7 ((x+7)/7)^2 - 3 # #= x^2/7+2 x+4# Answer link Related questions How do you find the second derivative of a parametric function? How do you find derivatives of parametric functions? How do you find #dy/dx# for the curve #x=t*sin(t)#, #y=t^2+2# ? How do you find the equation of the tangent to the curve #x=t^4+1#, #y=t^3+t# at the point... How do you find #(d^2y)/(dx^2)# for the curve #x=4+t^2#, #y=t^2+t^3# ? How do you find parametric equations of a tangent line? How do you find parametric equations for the tangent line to the curve with the given parametric... How do you find the equation of a line tangent to the curve at point #t=-1# given the parametric... How do you differentiate the following parametric equation: # x(t)=t^3-5t, y(t)=(t-3) #? How do you differentiate the following parametric equation: # x(t)=lnt, y(t)=(t-3) #? See all questions in Derivative of Parametric Functions Impact of this question 5290 views around the world You can reuse this answer Creative Commons License