How do you write the logarithmic expressions as a single logarithm #ln(x+2) - 2ln(x)#?

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Answer 1 · 2015-05-28T18:53:27

Use the following properties of logs:
1] #alogx=logx^a#
2] #logx-logy=log(x/y)#
So in your case:
#ln(x+2)-ln(x^2)=ln((x+2)/x^2)#