How do you write the equation #y= (x-4)(x-2)# in standard form? Precalculus Geometry of a Parabola Standard Form of the Equation 1 Answer AltairSafir Apr 11, 2018 #y=x^2-6x+8# Explanation: Just multiply each factor: #(x-4)(x-2)=x*x-2*x-4*x+8=# #=x^2-(2+4)x+8=# #=x^2-6x+8# Answer link Related questions How do I find the standard equation of a parabola? How do I find the standard equation of a parabola given 3 points? How do I find the focus of the parabola represented by #y=2x^2-8x+9#? What is the standard form of the equation for a parabola? In the standard form of the equation for a parabola, what is represented by #a#? What is the directrix of a parabola? How do I find the focus of the parabola with the equation #y=1/4x^2-3/2x+1/4#? How do you find an equation of the parabola with a vertex of (-1,2) and focus of (-1,0)? How do you write the polynomial #4x + x + 2# in standard form and how many terms and degree is it? How do you write the polynomial #1 - 2s + 5s^4# in standard form and how many terms and degree is it? See all questions in Standard Form of the Equation Impact of this question 1583 views around the world You can reuse this answer Creative Commons License