How do you write the equation $y+9= -3(x-2)$ in standard form?

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How do you write the equation $y+9= -3(x-2)$ in standard form?

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Answer 1 · 2016-03-10T00:38:17

$y=-3x-3$

Explanation:

Recall that the standard form of the equation of a line is:

$color(blue)(|bar(ul(color(white)(a/a)y=mx+bcolor(white)(a/a)|)$

where:
$y=$ y-coordinate
$m=$ slope
$x=$ x-coordinate
$b=$ y-intercept

Converting to Standard Form
$1$ . Start by simplifying the right side of the equation.

$y+9=-3(x-2)$

$y+9=-3x+6$

$2$ . Subtract $-9$ from both sides.

$y+9$ $color(red)(-9)=-3x+6$ $color(red)(-9)$

$3$ . Simplify.

$color(green)(|bar(ul(color(white)(a/a)y=-3x-3color(white)(a/a)|)$

Answer 2 · 2016-03-10T00:45:42

$y = -3x -3$

Explanation:

Given $y+9= -3(x-2)$ rewrite in standard form which for linear first order is: $y = mx+b$
$y+9 =-3x+6$ subtract 9 from both sides
$y = -3x+6-9 = -3x -3$ this the standard form
$y = -3x -3$

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How do you write the equation $y+9= -3(x-2)$ in standard form?

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How do you write the equation y+9= -3(x-2)y+9= -3(x-2) in standard form?

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Explanation:

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How do you write the equation $y+9= -3(x-2)$ in standard form?