How do you write the equation of the line that passes through the points (3, 4) and (–3, –8) in point-slope form?

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How do you write the equation of the line that passes through the points (3, 4) and (–3, –8) in point-slope form?

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Answer 1 · 2016-01-22T03:57:15

The equation is

$y = 2 x - 2$ $y=2x-2$

Explanation:

The two Points are -

$(3, 4); (- 3, - 8)$ $(3, 4);(-3, -8)$

Then -

$x_{1} = 3$ $x_1=3$
$y_{1} = 4$ $y_1=4$
$x_{2} = - 3$ $x_2=-3$
$y_{2} = - 8$ $y_2=-8$

The formula you have to use is -

$(y - y_{1}) = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1})$ $(y-y_1)=(y_2-y_1)/(x_2-x_1)(x-x_1)$
$y - 4 = \frac{- 8 - 4}{- 3 - 3} (x - 3)$ $y-4=(-8-4)/(-3-3)(x-3)$
$y - 4 = \frac{- 12}{- 6} (x - 3)$ $y-4=(-12)/(-6)(x-3)$
$y - 4 = 2 (x - 3)$ $y-4=2(x-3)$
$y - 4 = 2 x - 6$ $y-4=2x-6$
$y = 2 x - 6 + 4$ $y=2x-6+4$

The equation is

$y = 2 x - 2$ $y=2x-2$

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How do you write the equation of the line that passes through the points (3, 4) and (–3, –8) in point-slope form?

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Explanation:

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