How do you write the equation of the line that passes through the points (2,5) and (6,2)?

1 Answer
Binayaka C.
Jan 31, 2017

The equation of line in slope-intercept form is # y = -3/4 x +6 1/2#
The equation of line in standard form is # 3x + 4y = 26#

Explanation:

The slope of the line passing through #(2,5) and (6,2)# is #m= (y_2-y_1)/(x_2-x_1)= (2-5)/(6-2)=-3/4#

Let the equation of the line in slope-intercept form be #y=mx+c or y=-3/4x+c# The point (2,5) will satisfy the equation . So, # 5= -3/4*2+c or c= 5+3/2= 13/2#

Hence the equation of the line in slope-intercept form is #y= -3/4x+13/2 or y = -3/4 x +6 1/2#

The equation of the line in standard form is #y= -3/4 x+13/2. or 4y =-3x+26 or 3x + 4y = 26# [Ans]

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