How do you write the equation of the line parallel to the line x + 4y = 6 and passes through (-8, 5)?

1 Answer
Gió
Apr 24, 2016

I found #x+4y=12#

Explanation:

We can use the general relationship for the equation of a line passing through #(x_0,y_0)# and slope #m# as:
#y-y_0=m(x-x_0)#
to be parallel the slope must be the same of your original line.
We write the original line (collecting #y#) as:
#y=-1/4x+6/4#
whose slope is #-1/4#
so we can find our parallel as:
#y-5=-1/4[x-(-8)]#
#4y-20=-x-8#
so the equation will be:
#x+4y=12#

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