How do you write the equation of the line in slope intercept form that passes through the points (2, -5) and (0, 1)?

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Answer 1 · 2016-10-22T14:59:58

#y = -3x + 1#

The #y# intercept form is #y = mx + b#

#m# = the slope of the line (think m mountain slope)
#b# = the #y# intercept ( think beginning the value of #y# when #x =0#

To find the slope use the equation

#( y_1 - y_2)/(x_1 - x_2) = m #

substituting the values for the points given

# (-5 - 1)/(2-0) = m # This gives

# -6/2 = -3 = m#

putting this value into the #y# intercept form gives

#y = -3x + b#

Substituting into the second equation gives

# 1 = (-3) xx 0 + b# Solving this results in

#1 = b# substituting this value into the #y# intercept form gives

#y = -3x + 1#