How do you write the equation of a line through (0,3) and (-2,5)?
1 Answer
Nov 16, 2016
Explanation:
The equation of a line in
#color(blue)"slope-intercept form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#
where m represents the slope and b, the y-intercept.We require to find m and b.
To find m use the
#color(blue)"gradient formula"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(m=(y_2-y_1)/(x_2-x_1))color(white)(2/2)|)))#
where# (x_1,y_1)" and " (x_2,y_2)" are 2 points on the line"# The 2 points here are (0 ,3) and (-2 ,5)
let
# (x_1,y_1)=(0,3)" and " (x_2,y_2)=(-2,5)#
#rArrm=(5-3)/(-2-0)=2/(-2)=-1# One of the points here is (0 ,3). That is where the line crosses the y-axis.
Hence the value of b is 3
#rArry=-x+3" is the equation"#
