How do you write the equation of a line in slope intercept, point slope and standard form given (3, -2) and (-2, 3)?

1 Answer
Jun 11, 2018

#"1. Point - Slope form of equation is " y + 2 = - (x -3)#

#"2. Slope - intercept form is "y = -x + 1#

#3. "Standard form is " x = y = 1#

Explanation:

![https://www.onlinemathlearning.com/http://forms-linear-equations.html](https://useruploads.socratic.org/SMXCOxwtQz680Ewo3v2u_forms%20of%20linear%20equations.png)

#(x_1, y_1) (3, -2), (x_2, y_2) = (-2,3)#

#"Slope " m = (y_2 - y_1) / (x_2 - x_1) = (3 + 2) / (-2 -3) = -1#

#"1. Point - Slope form of equation is "#

#y - y_1 = m (x - x_1) = y + 2 = -1 * (x - 3)#

#y + 2 = - (x -3)#

#"2. Slope - intercept form is "#

#y = mx + c = -x + 1#

#3. "Standard form is " x = y = 1#