How do you write the equation of a line in slope intercept, point slope and standard form given (3, -2) and (-2, 3)?

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Answer 1 · 2018-06-11T02:41:49

#"1. Point - Slope form of equation is " y + 2 = - (x -3)#

#"2. Slope - intercept form is "y = -x + 1#

#3. "Standard form is " x = y = 1#

#(x_1, y_1) (3, -2), (x_2, y_2) = (-2,3)#

#"Slope " m = (y_2 - y_1) / (x_2 - x_1) = (3 + 2) / (-2 -3) = -1#

#"1. Point - Slope form of equation is "#

#y - y_1 = m (x - x_1) = y + 2 = -1 * (x - 3)#

#y + 2 = - (x -3)#

#"2. Slope - intercept form is "#

#y = mx + c = -x + 1#

#3. "Standard form is " x = y = 1#