How do you write the equation of a line given (-6,6),(3,3)?

Question

1515 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-31T22:10:30

#x+3y-12=0#

The equation of a line joining #(x_1,y_1)# and #(x_2,y_2)# is given by

#(y-y_1)/(y_2-y_1)=(x-x_1)/(x_2-x_1)#

Hence line joining #(-6,6)# and #(3,3)# is given by

#(y-6)/(3-6)=(x-(-6))/(3-(-6))# or

#(y-6)/-3=(x+6)/(3+6)# or

#9×(y-6)=-3×(x+6)# or

#9y-54=-3x-18# or

#3x+9y-54+18=0# or

#3x+9y-36=0# and dividing by #3#

#x+3y-12=0#