How do you write the equation of a line for (8,3)(-8,-3)?

First, we need to determine the slope of the line. The formula for find the slope of a line is:

#m = (color(red)(y_2) - color(blue)(y_1))/(color(red)(x_2) - color(blue)(x_1))#

Where #(color(blue)(x_1), color(blue)(y_1))# and #(color(red)(x_2), color(red)(y_2))# are two points on the line.

Substituting the values from the points in the problem gives:

#m = (color(red)(-3) - color(blue)(3))/(color(red)(-8) - color(blue)(8)) = (-6)/-16 = 6/16 = 3/8#

Now, we can use the point slope formula to write and equation for the line. The point-slope form of a linear equation is: #(y - color(blue)(y_1)) = color(red)(m)(x - color(blue)(x_1))#

Where #(color(blue)(x_1), color(blue)(y_1))# is a point on the line and #color(red)(m)# is the slope.

Substituting the slope we calculated and the values from the first point in the problem gives:

#(y - color(blue)(3)) = color(red)(3/8)(x - color(blue)(8))#

We can also substitute the slope we calculated and the values from the second point in the problem giving:

#(y - color(blue)(-3)) = color(red)(3/8)(x - color(blue)(-8))#

#(y + color(blue)(3)) = color(red)(3/8)(x + color(blue)(8))#