How do you write the equation of a direct variation that includes the point (-6,1)?

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Answer 1 · 2016-03-09T15:24:24

Equation of direct variation is: $" "y=(-1/6)x$

Let $(x,y) ->(-6,1)$

The term 'direct variation implies that we have the structure of

Let $k$ be a constant of variation

Then $y=kx$ ....................(1)

We are given that $(x,y)->(-6,1)$ so by substitution equation (1) becomes

$1=k(-6)$

Divide both sides by -6

$1/(-6)=kxx(-6)/(-6)$

But $(-6)/(-6)=1$ giving

$-1/6=k$
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Equation of direct variation is: $" "y = kx" "->" "y=(-1/6)x$