How do you write the equation in standard form 5y-1/3x=-8?

2 Answers
Moose21
Apr 19, 2018

#y=(24x+1)/5#

Explanation:

#(5y-1)/(3x)=8#
#(5y-1)=8(3x)#
#5y-1=24x#
#5y=24x+1#
#y=(24x+1)/5#

The standard form for a linear equation is in the form #y=x+b#, therefore, we want to isolate y. To do this, first, we want to get rid of the denominator, which is done by multiplying both sides of the equation by #3x#. The denominator would cancel out on the left side. Then add #1# to both sides of the equation to remove it from the left side. After isolating #5y#, #y# can be isolated by dividing both sides by #5#. This gives the answer, #y=(24x+1)/5#.

Jim G.
Apr 19, 2018

#x-15y=24#

Explanation:

#"the equation of a line in "color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#

#"where A is a positive integer and B, C are integers"#

#"multiply all terms by "-3#

#rArr-15y+x=24#

#rArrx-15y=24larrcolor(red)"in standard form"#

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