How do you write the equation in standard form 5y-1/3x=-8?

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How do you write the equation in standard form 5y-1/3x=-8?

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Answer 1 · 2018-04-19T07:30:10

$y=(24x+1)/5$

Explanation:

$(5y-1)/(3x)=8$
$(5y-1)=8(3x)$
$5y-1=24x$
$5y=24x+1$
$y=(24x+1)/5$

The standard form for a linear equation is in the form $y=x+b$ , therefore, we want to isolate y. To do this, first, we want to get rid of the denominator, which is done by multiplying both sides of the equation by $3x$ . The denominator would cancel out on the left side. Then add $1$ to both sides of the equation to remove it from the left side. After isolating $5y$ , $y$ can be isolated by dividing both sides by $5$ . This gives the answer, $y=(24x+1)/5$ .

Answer 2 · 2018-04-19T07:37:13

$x-15y=24$

Explanation:

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How do you write the equation in standard form 5y-1/3x=-8?

2 Answers

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