How do you write the equation in slope intercept form given (-3,13) and (-1,-1)?

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Answer 1 · 2017-09-11T19:28:08

The line's equation is

#y=-7x-8#

See explanation.

If 2 points of a line #A=(x_A;y_A)# and #B=(x_B;y_B)# are given, then the line's slope #a# can be calculated as:

Here we have:

#a=(-1-13)/(-1-(-3))=-14/2=-7#

Now we have to find the #b# term for which one of the points lies on the line:

#-1=-7*(-1)+b#

#b=-1-7#

#b=-8#

Now we can write the function: