How do you write the equation in slope intercept form given (-3,13) and (-1,-1)?

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How do you write the equation in slope intercept form given (-3,13) and (-1,-1)?

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Answer 1 · 2017-09-11T19:28:08

The line's equation is

$y = - 7 x - 8$ $y=-7x-8$

See explanation.

Explanation:

If 2 points of a line $A = (x_{A}; y_{A})$ $A=(x_A;y_A)$ and $B = (x_{B}; y_{B})$ $B=(x_B;y_B)$ are given, then the line's slope $a$ $a$ can be calculated as:

$a = \frac{y_{B} - y_{A}}{x_{B} - x_{A}}$ $a=(y_B-y_A)/(x_B-x_A)$

Here we have:

$a = \frac{- 1 - 13}{- 1 - (- 3)} = - \frac{14}{2} = - 7$ $a=(-1-13)/(-1-(-3))=-14/2=-7$

Now we have to find the $b$ $b$ term for which one of the points lies on the line:

$- 1 = - 7 \cdot (- 1) + b$ $-1=-7*(-1)+b$

$b = - 1 - 7$ $b=-1-7$

$b = - 8$ $b=-8$

Now we can write the function:

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How do you write the equation in slope intercept form given (-3,13) and (-1,-1)?

1 Answer

$y = - 7 x - 8$ $y=-7x-8$

Explanation:

$a = \frac{y_{B} - y_{A}}{x_{B} - x_{A}}$ $a=(y_B-y_A)/(x_B-x_A)$

$y = - 7 x - 8$ $y=-7x-8$

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How do you write the equation in slope intercept form given (-3,13) and (-1,-1)?

1 Answer

y=−7x−8y=-7x-8

Explanation:

a=yB−yAxB−xAa=(y_B-y_A)/(x_B-x_A)

y=−7x−8y=-7x-8

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$y = - 7 x - 8$ $y=-7x-8$

$a = \frac{y_{B} - y_{A}}{x_{B} - x_{A}}$ $a=(y_B-y_A)/(x_B-x_A)$

$y = - 7 x - 8$ $y=-7x-8$