How do you write the equation in slope intercept form given (2,5) and (7,-3)?

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Answer 1 · 2016-05-16T19:25:21

The slope-intercept form of the equation of the line is
$y = -8/5x +25/5$

The formula for the slope of a line based upon two coordinate points is

$m = (y_2-y_1)/(x_2-x_1)$

For the coordinate points $(2,5) and (7,-3)$
$x_1 = 2$
$x_2 = 7$
$y_1 = 5$
$y_2 = -3$

$m = (-3-5)/(7-2)$

$m = -8/5$

The slope is $m = -8/5$

The point slope formula would be written as
$y - y_1 = m( x - x_1)$

$m = -8/5$
$x_1 = 2$
$y_1=5$

$y - 5 = -8/5 (x -2)$

$y - 5 = -8/5x +16/5$

$y cancel(-5) cancel(+ 5)= -8/5x +16/5 +5$

$y = -8/5x +16/5 +25/5$

The slope-intercept form of the equation of the line is
$y = -8/5x +25/5$

The standard form would be
$5y = -8x +25$