How do you write the equation given (-4,-8); (-2,0)?

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Answer 1 · 2018-05-02T01:23:32

#y=4x+8#

Slope-intercept form: #y=mx+b# where #m# is the slope and #b# is the y-intercept

Slope through two points: #(y_2-y_1)/(x_2-x_1)#

#(0-(-8))/(-2-(-4))#

#8/2#

#4#

Our current equation is #y=4x+b#

Let's plug in the point #(-2, 0)# to find #b#:

#0=4*-2+b#

#0=-8+b#

#b=8#

The equation is #y=4x+8#