How do you write the equation for a circle with center at (-1,3) passes through the point (-1,4)?

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Answer 1 · 2016-04-22T09:59:44

#(x+1)^2+(y-3)^2=1#

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#O=(-1,3)#
#P=(-1,4)#

#r=sqrt((-1+1)^2+(4-3)^2#

#r=sqrt(0+1)#

#r=1 " radius of circle"#

#"general equation for circle which it has a center of (a,b) and a radius of r"#
#(x-a)^2+(y-b)^2=r^2#

#r=1" "a=-1" "b=3#

#(x+1)^2+(y-3)^2=1#