How do you write the equation alpha=sinbeta in the form of an inverse function? Trigonometry Inverse Trigonometric Functions Inverse Trigonometric Properties 1 Answer Shwetank Mauria Dec 23, 2016 In the form of an inverse function alpha=sinbeta can be written as beta=sin^(-1)alpha or beta=arcsinalpha Answer link Related questions How do you use the properties of inverse trigonometric functions to evaluate tan(arcsin (0.31))? What is \sin ( sin^{-1} frac{sqrt{2}}{2})? How do you find the exact value of \cos(tan^{-1}sqrt{3})? How do you evaluate \sec^{-1} \sqrt{2} ? How do you find cos( cot^{-1} sqrt{3} ) without a calculator? How do you rewrite sec^2 (tan^{-1} x) in terms of x? How do you use the inverse trigonometric properties to rewrite expressions in terms of x? How do you calculate sin^-1(0.1)? How do you solve the inverse trig function cos^-1 (-sqrt2/2)? How do you solve the inverse trig function sin(sin^-1 (1/3))? See all questions in Inverse Trigonometric Properties Impact of this question 1765 views around the world You can reuse this answer Creative Commons License