How do you write the electron configuration for the following ions?

K^+1
Br-1
Al+3
As-3?

1 Answer
anor277
Dec 21, 2017

K^+, Z=19; 1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)...

...the 4s^(1) electron is lost upon ionization.....

Explanation:

Br^-, Z=35; 1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(10)4s^(2)4p^6...

...the 4p electron is FILLED upon ionization.....

Al^(3+), Z=13; 1s^(2)2s^(2)2p^(6)...the 3s and 3p electrons have been lost....

As^(3-), Z=33; 1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(10)4s^(2)4p^6...and note that this configuration is the same as that of Br^-, i.e. isoelectronic with krypton....

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