How do you write the complex number in trigonometric form #3i#?

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How do you write the complex number in trigonometric form #3i#?

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Answer 1 · 2016-10-30T13:48:15

the trigonometric form is #3(cos(pi/2)+isin(pi/2))#

Explanation:

This complex number has only the imaginary part:
so, #cos theta=0# and #sintheta=1#
So #theta=pi/2#
So the trigonometric form is #3(cos(pi/2)+isin(pi/2))#
and you can also write it as #3e^(ipi/2)#

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How do you write the complex number in trigonometric form #3i#?

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