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How do you write the complex number in trigonometric form #-3-i#?

1 Answer

Jan 6, 2018

#sqrt10*Cis(pi+arctan(1/3))#

Explanation:

Magnitute of z=-3-i; #r=sqrt((-3)^2+(-1)^2)=sqrt10#

Argument of z; #Arg(z)=arctan((-1)/(-3))=arctan(1/3)#

However, z found in 3rd quadrant. Hence,

#z=sqrt10*Cis(pi+arctan(1/3))#

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