How do you write the complex number in trigonometric form #2+2i#?
1 Answer
Jun 15, 2017
Explanation:
#"to convert from "color(blue)"standard to trigonometric form"#
#"that is " x+yitor(costheta+isintheta)" where "#
#• r=sqrt(x^2+y^2)#
#• theta=tan^-1(y/x)#
#"here " x=2" and " y=2#
#rArrr=sqrt(2^2+2^2)=sqrt8=2sqrt2#
#theta=tan^-1(2/2)=tan^-1(1)=pi/4#
#rArr2+2i=2sqrt2(cos(pi/4)+isin(pi/4))#
