How do you write #q^2 – 12q + 36# in factored form?

3 Answers
Harold Walden
Sep 21, 2015

#q^2-12q+36=(q-6)^2#

Explanation:

So, to factorise this quadratic expression we need to find numbers that add together to make -12 and multiply together to make +36. The only two numbers that do this are -6 and -6.

Or,

#q^2-12q+36=(q-6)(q-6)=(q-6)^2#

Nallasivam V
Sep 21, 2015

#(q-6)^2#

Explanation:

It is a perfect square -
#q^2 -6q-6q+36#
#q(q -6)-6(q-6)#
#(q -6)(q-6)#
#(q-6)^2#

Rafael
Sep 21, 2015

#(q-6)^2#

Explanation:

Actually, if you look at it closely, you'll realize that #q^2-12q+36# is a perfect square trinomial. You can write it down as #(q-6)(q-6)# or simply #(q-6)^2#.

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