How do you write #log_125 25 = 2/3?# as an exponential form?
1 Answer
Mar 14, 2018
Explanation:
#"using the "color(blue)"law of logarithms"#
#•color(white)(x)log_b x=nhArrx=b^n#
#"here "b=125,x=25" and "n=2/3#
#rArrlog_(125) 25=2/3hArr25=125^(2/3)#