How do you write the equation of the line that passes through (-6, -4) and (2, -5)?

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Answer 1 · 2016-06-02T13:46:41

You must first find the slope.

#m = (y_2 - y_1)/(x_2 - x_1)#

#m = (-5 - (-4))/(2 - (-6))#

#m = -1/8#

Now, use point slope form, one of your points and the slope that we found to convert the equation to slope intercept form, #y = mx + b#.

#y - y_1 = m(x - x_1)#

#y - (-5) = -1/8(x -2)#

#y + 5 = -1/8x + 1/4#

#y = -1/8x -19/4#

You have your equation!

Hopefully this helps!