How do you write an equation of the line parallel to the line 10x - 5y = 8 and passing through the point (2,4)?

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Answer 1 · 2018-03-21T12:12:48

The equation the line is #2x-y=0#

The equation of a line is #10x-5y-8=0; (1)#

Parallal lines have equal slopes . Therefore the equation of a line

parallal to #10x-5y-8=0# is #10x-5y+c=0 ; (2)# The point

#(2,4)# is on the line so , it will satisfy the equation (2).

# :. 10*2-5*4+c=0 or 20-20+c=0 :. c=0#

So , the equation the line is

#10x-5y+0=0 or 10x-5y=0 or 2x-y=0# [Ans]