How do you write an equation of the horizontal line passing through the point (-7,4)?

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How do you write an equation of the horizontal line passing through the point (-7,4)?

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Answer 1 · 2018-03-14T09:22:47

$y=4$

Explanation:

$"A horizontal line is parallel to the x-axis and passes "$
$"through all points in the plane with the same y-coordinate"$

$"the equation is "y=c$

$"where c is the value of the y-coordinate the line passes"$
$"through"$

$"the point here is "(-7,4)$

$rArry=4" is the equation of the line"$
graph{(y-0.001x-4)((x+7)^2+(y+4)^2-0.04)=0 [-10, 10, -5, 5]}

Answer 2 · 2018-03-14T09:38:43

$y = 4$

Explanation:

A horizontal line has a slope of $0$ and thus pases through all points of $x in RR$ Which includes $x=-7$

The equation of a straight line with slope $(m)$ and $y-$ intercept $(c)$ is:

$y=mx+c$

In this case $m=0 and c = 4$

Hence, $y=4$ is the equation of our straight line. as shown in the graphic below.

graph{(y-0.000x-4)((x+7)^2+(y-4)^2-0.1)=0 [-14.24, 14.24, -7.12, 7.12]}

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How do you write an equation of the horizontal line passing through the point (-7,4)?

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