How do you write an equation of the horizontal line passing through the point (-7,4)?

2 Answers
Jim G.
Mar 14, 2018

#y=4#

Explanation:

#"A horizontal line is parallel to the x-axis and passes "#
#"through all points in the plane with the same y-coordinate"#

#"the equation is "y=c#

#"where c is the value of the y-coordinate the line passes"#
#"through"#

#"the point here is "(-7,4)#

#rArry=4" is the equation of the line"#
graph{(y-0.001x-4)((x+7)^2+(y+4)^2-0.04)=0 [-10, 10, -5, 5]}

Alan N.
Mar 14, 2018

#y = 4#

Explanation:

A horizontal line has a slope of #0# and thus pases through all points of #x in RR# Which includes #x=-7#

The equation of a straight line with slope #(m)# and #y-#intercept #(c)# is:

#y=mx+c#

In this case #m=0 and c = 4#

Hence, #y=4# is the equation of our straight line. as shown in the graphic below.

graph{(y-0.000x-4)((x+7)^2+(y-4)^2-0.1)=0 [-14.24, 14.24, -7.12, 7.12]}

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