How do you write an equation of a line through (6, 2); parallel to #4x-y=3#?

1 Answer
Gió
Dec 5, 2016

I got: #4x-y=22#

Explanation:

We can use the general expression for a line through a point of coordinates #(x_0,y_0)# and slope #m# as:

#y-y_0=m(x-x_0)#

The slope must be the same of the slope of the original line in order to be parallel.

The original line can be written (collecting #y#) as:
#y=4x-3#
where the slope will be: #m=4# (the coefficient of #x#):
so we have:
#y-2=4(x-6)#
#y=4x-24+2#
#y=4x-22#
or
#4x-y=22#

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