How do you write an equation of a line through (3,3) and parallel to y= 2/3x -1?

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Answer 1 · 2017-04-04T05:54:16

$y=2/3x+1$

Our reference line is: $y=2/3x-1$

Hence the slope of the reference line is: $2/3$

Any straight line parallel to the reference line will have a slope of $2/3$

We are asked to find the equation of the line parallel to the reference line passing through the point $(3,3)$ .

The equation of a straight line passing through point $(x_1, y_1)$ is:

$(y-y_1) =m(x - x_1)$ Where $m$ is the slope of the line.

Hence the equation of our required line will be:

$(y-3) = 2/3(x-3)$

$3(y-3) = 2(x-3)$

$3y-9 = 2x-6$

$3y= 2x+3$

$y = 2/3x+1$