How do you write an equation of a line parallel to y=3 passing through P(-2,4)?

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How do you write an equation of a line parallel to y=3 passing through P(-2,4)?

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Answer 1 · 2015-06-19T19:28:03

#y=4#

Explanation:

Your line, #y=3# is a horizontal line passing through #3# (on the y axis). A line parallel to this one has to be again horizontal but this time passing through #4#, i.e. #y=4#.

A somewhat more rigorous approach would be to say that the slope #m# of #y=3# is zero so using the relationship:
#y-y_0=m(x-x_0)#
you get:
#y-4=0(x+2)#
#y=4#

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How do you write an equation of a line parallel to y=3 passing through P(-2,4)?

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