How do you write an equation of a line going through (4,1) parallel to y=1/3x+3?

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How do you write an equation of a line going through (4,1) parallel to y=1/3x+3?

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Answer 1 · 2018-05-05T09:33:31

#x-3y-1=0#

Explanation:

When a line is parallel to another line, that means that their gradients are the same ie your new line will have the gradient #m=1/3# since #y=1/3x+3# is in the general form #y=mx+b# where m is the gradient

Using the point-gradient method,

#(y-1)=1/3(x-4)#

#3y-3=x-4#
#x-3y-1=0#

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How do you write an equation of a line going through (4,1) parallel to y=1/3x+3?

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