How do you write an equation of a line going through (-2,-3), (2,-1)?

1 Answer
May 10, 2017

#y=1/2x-2#

Explanation:

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#
where m represents the slope and b, the y-intercept.

#"to calculate m, use the "color(blue)"gradient formula"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(m=(y_2=y_1)/(x_2-x_1))color(white)(2/2)|)))#
where # (x_1,y_1),(x_2,y_2)" are 2 coordinate points"#

#"the 2 points here are "(-2,-3)" and " (2,-1)#

#"let " (x_1,y_1)=(-2,-3)" and " (x_2,y_2)=(2,-1)#

#rArrm=(-1-(-3))/(2-(-2))=2/4=1/2#

#rArry=1/2x+blarr" is the partial equation"#

#"to find b, substitute either of the 2 given points into equation"#

#"using " (2,-1)#

#-1=(1/2xx2)+brArrb=-2#

#rArry=1/2x-2larrcolor(red)" in slope-intercept form"#