How do you write an equation of a line given point (-3,0) and (1,-6)?

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How do you write an equation of a line given point (-3,0) and (1,-6)?

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Answer 1 · 2016-07-03T10:55:28

The equation of the line is #y=-3/2x-9/2#

Explanation:

The slope of the line passing through the given points is #m=(y_2-y_1)/(x_2-x_1)=(-6-0)/(1-(-3))=-6/4=-3/2# The equation of the line passing through point #(-3,0)# is # y-y_1=m(x-x_1) or y-0=-3/2(x+3)or y=-3/2x-9/2# graph{(-3/2)*x-9/2 [-10, 10, -5, 5]}[Ans]

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How do you write an equation of a line given point (-3,0) and (1,-6)?

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